Two passengers leave the airport at Kansas City, Missouri. One flies to Los Angeles, California, in 3.4 hr and the other flies in the opposite direction to New York City in 2.4 hr. With prevailing westerly winds, the speed of the plane to New York City is 60 mph faster than the speed of the plane to Los Angeles. If the total distance traveled by both planes is 2464 mi, determine the average speed of each plane.

Answer:  x = 400 MPH    x+60 = 460 MPHStep-by-step explanation: (Distance = (Rate)(Time) Let x = speed of the LA bound plane Then, x+60 = speed of NYC bound plane Sum of distances = 2464 3.4x + 2.4(x+60) = 2464          5.8x + 144 = 2464                   5.8x = 2320                       x = 400 MPH    x+60 = 460 MPH