MATH SOLVE

5 months ago

Q:
# Which equation, when graphed, has x-intercepts at (2, 0) and (4, 0) and a y-intercept of (0, –16)?f(x) = –(x – 2)(x – 4)f(x) = –(x + 2)(x + 4)f(x) = –2(x – 2)(x – 4)f(x) = –2(x + 2)(x + 4)

Accepted Solution

A:

f(x)= -2 (x - 2) ( x - 4)

if x=2 ⇒ f(x)=y=0 ⇒ graph of f(x) intercept x axis in (2,0)

if x=4 ⇒ f(x)=y=0 ⇒ graph of f(x) intercept x axis in (4,0)

if x=0 ⇒f(x)= -2 *(-2)*(-4)= - 16 ⇒ graph of f(x) intercept y axis in (0,- 16)

⇒ f(x)= -2 (x - 2) ( x - 4) is the answer

if x=2 ⇒ f(x)=y=0 ⇒ graph of f(x) intercept x axis in (2,0)

if x=4 ⇒ f(x)=y=0 ⇒ graph of f(x) intercept x axis in (4,0)

if x=0 ⇒f(x)= -2 *(-2)*(-4)= - 16 ⇒ graph of f(x) intercept y axis in (0,- 16)

⇒ f(x)= -2 (x - 2) ( x - 4) is the answer